smallest 3 digit number divisible by 6 8 12|Find the smallest 3 digit number exactly divisible by 6, : Clark SOLUTION : First find the LCM of 6,8,12. LCM by prime factorization method : 6 = 2¹ × 3¹. 8 = 2³. 12 = 2² × 3. LCM (6,8,12) = 2³ × 3¹ = 8 × 3 = 24. [Product of the greatest power of each prime factor involved in the .
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smallest 3 digit number divisible by 6 8 12,Now we will divide the smallest 3-digit number with the LCM obtained, and the remainder will be subtracted from the dividend, and 24 will be added to it to make it perfectly divisible. ∴ 100 24 = 4, Remainder = 4. According to the above statement. = (100 – 4) + 24 = 96 + 24 = 120. Hence, .
We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is exactly .So, the smallest three digit multiple of 24 will be, 100 = (100 – 4) + 24 = 96 + 24 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12, is 120. You can also .
The smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. In Mathematics, the LCM is the value which is evenly divisible by the given two numbers. A .
LCM of 6, 8 and 12 = 2×2×2×3 = 24. The smallest 3-digit number = 100. To find the smallest 3-digit number possible we have to look for smallest 3-digit multiples of 24. Multiples of 24 = . SOLUTION : First find the LCM of 6,8,12. LCM by prime factorization method : 6 = 2¹ × 3¹. 8 = 2³. 12 = 2² × 3. LCM (6,8,12) = 2³ × 3¹ = 8 × 3 = 24. [Product of the greatest power of each prime factor involved in the .smallest 3 digit number divisible by 6 8 12 SOLUTION : First find the LCM of 6,8,12. LCM by prime factorization method : 6 = 2¹ × 3¹. 8 = 2³. 12 = 2² × 3. LCM (6,8,12) = 2³ × 3¹ = 8 × 3 = 24. [Product of the greatest power of each prime factor involved in the .
Find the smallest 3 digit number exactly divisible by 6, Question. Determine the smallest 3− digit number which is exactly divisible by 6, 8 and 12. Solution. Verified by Toppr. Smallest number divisible by 6, 8, 12 = L.C.M of 6, 8, 12. .Smallest number = LCM of 6, 8, 12. We have to find the smallest 3-digit multiple of 24. It can be seen that. 24 4 = 96 and. 24 5 = 120. Hence, the smallest 3-digit number which is exactly .We have to find the smallest three digit number which is divisible by 6, 8, 12. Solution : The smallest 3-digit which is exactly divisible by 6,8 and 12 will be a multiple of LCM of 6,8 and 12.
Hence, the smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. This is the required answer. Note: In such types of questions it is always advisable to divide .
We know that the divisibility test of 6 states that a number is divisible by 6 if the number is even and the sum of the digits is divisible by 3. Hence, 100002 is the smallest number divisible by 6 as it is even and the sum of digits 1 + 0 + 0 + 0 + 0 + 2 = 3. So 100 is the smallest 3 digit number in the number system. Smallest three digit number in the number system = 100 = 100 – 1 = 99 (which is a 2 digit number) Hence it is proved that 100 is the smallest three-digit number. What is the smallest 3-digit number if all digits are unique? Answer: As in the above explanation that 100 is the smallest . SOLUTION : First find the LCM of 6,8,12 LCM by prime factorization method : 6 = 2¹ × 3¹ 8 = 2³ 12 = 2² × 3 LCM(6,8,12) = 2³ × 3¹ = 8 × 3 = 24 [Product of the greatest power of each prime factor involved in the .
Smallest three digit number divisible by 6 8 12Question 4 Determine the smallest 3 digit number which is exactly divisible by 6,8 and 12 . Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. . Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Open in App. Solution. The least common multiple (LCM) of 2 or more numbers is the smallest number . Determine the smallest 3 digit number which is exactly divisible by 6, 8, and 12. Answer: To find the smallest three-digit number which is exactly divisible by 6, 8, and 12, we can follow these steps: Find the Least Common Multiple (LCM) of 6, 8, and 12: First, find the prime factorizations of each number:Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Q. Find the smallest 6 digit number which is exactly divisible by 8, 15 and 18. Q. Find the smallest and the largest four-digit numbers which when lessened by 12 are exactly divisible by 16 , 24 a n d 40 .The sum of all 3-digit numbers divisible by 12 is 41400. What is the smallest three digit number divisible by 12? The smallest or lowest 3-digit number divisible by 12 is the first number on the list above (first 3 digit number divisible by 12). As you can see, that number is 108. What is the largest three digit number divisible by 12?A number is divisible by 5 if its last digit is a 5 or a 0. A number is divisible by 6 if it is divisible by 2 and 3, i.e. if it is even and its sum and digits are divisible by 3. A number is divisible by 8 if its last three digits are divisible by 8. A number is divisible by 9 if its sum of digits is divisible by 9. A number is divisible by 10 .
Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12. Use app ×. Login . L.C.M. of 6, 8 and 12 = 2 x 2 x 2 x 3 = 24. The smallest 3-digit number = 100 . To find the number, we have to divide 100 by 24. Therefore, the required number = 100 + . Therefore multiply 24 with 5. Now we get the three digit number 120. Therefore 120 is the smallest three digit number divisible by 6, 8 and 12. plzz mark me as brainliest. Advertisement . Step-by-step explanation: LCM of 6,8,12 is 24 the smallest 3 digit no. that can be divided by 6,8,12 will also be divided by 24 =>24×4=96 =>(24×5=120 .A number is divisible by 6 if the number is divisible by both 2 and 3. Example 1: Is the number 255 divisible by 6? Solution: For the number 255 to be divisible by 6, it must divisible by 2 and 3. Let’s check first if it is divisible by 2. Note that 255 is not an even number (any number ending in 0, 2, 4, 6, or 8) which makes it not divisible 2.
Determine the smallest 3-digit number which is exactly divisible by 6, 8, and 12. Answer: To find the smallest 3-digit number which is exactly divisible by 6, 8, and 12, follow these steps: Find the Least Common Multiple (LCM) of 6, 8, and 12: First, find the prime factorizations of 6, 8, and 12. We need to find the LCM of the given number . Calculation . LCM of (6, 8, 12, 20) = 120 . Now, find the smallest four-digit no. which is divisible by 120 . So, 1080 is divisible by 120 . Required number = 1080 + 5 = 1085 . ∴ The smallest number of 4 digits which when divided by 6, 8, 12, and 20 leaves a remainder 5 in each case is 1085 Smallest number = LCM of 6, 8, 12. LCM = 2 × 2 × 2 × 3 = 24. the smallest 3-digit multiple of 24. It can be seen that 24 × 4 = 96 and 24 × 5 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120As we know that the greatest 3-digit number is 999, we will now divide 999 by the obtained LCM that is 120. Since the remainder is not 0, hence we subtract 39 from 999. 999 - 39 = 960 which is a multiple of 120 and is exactly divisible. Now, 120 × 8 = 960 and 120 × 9 = 1080. We see that 120 × 9 = 1080 is a 4-digit number but, we need the .We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is exactly divisible by $$6, 8$$ and $$12$$ is $$120$$.
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